.12=2(x)^2+(20/x)

Solution for .12=2(x)^2+(20/x) equation:

.12=2(x)^2+(20/x)

We move all terms to the left:

.12-(2(x)^2+(20/x))=0


Domain of the equation: x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(2x^2+(+20/x))+.12=0

We add all the numbers together, and all the variables

-(2x^2+(+20/x))+0.12=0

We multiply all the terms by the denominator


-(2x^2+(+20+(0.12)*x))=0


We calculate terms in parentheses: -(2x^2+(+20+(0.12)*x)), so:

2x^2+(+20+(0.12)*x)


We calculate terms in parentheses: +(+20+(0.12)*x), so:

+20+(0.12)*x

determiningTheFunctionDomain
(0.12)*x+20

We multiply parentheses

0.12x+20

Back to the equation:

+(0.12x+20)


We get rid of parentheses

2x^2+0.12x+20

Back to the equation:

-(2x^2+0.12x+20)


We get rid of parentheses

-2x^2-0.12x-20=0

a = -2; b = -0.12; c = -20;
Δ = b2-4ac
Δ = -0.122-4·(-2)·(-20)
Δ = -159.9856
Delta is less than zero, so there is no solution for the equation